50x^2+100x-70=0

Solution for 50x^2+100x-70=0 equation:

50x^2+100x-70=0

a = 50; b = 100; c = -70;
Δ = b2-4ac
Δ = 1002-4·50·(-70)
Δ = 24000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{24000}=\sqrt{1600*15}=\sqrt{1600}*\sqrt{15}=40\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-40\sqrt{15}}{2*50}=\frac{-100-40\sqrt{15}}{100}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+40\sqrt{15}}{2*50}=\frac{-100+40\sqrt{15}}{100}
$